305=16x^2

Solution for 305=16x^2 equation:

305=16x^2

We move all terms to the left:

305-(16x^2)=0

a = -16; b = 0; c = +305;
Δ = b2-4ac
Δ = 02-4·(-16)·305
Δ = 19520
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{19520}=\sqrt{64*305}=\sqrt{64}*\sqrt{305}=8\sqrt{305}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{305}}{2*-16}=\frac{0-8\sqrt{305}}{-32}
=-\frac{8\sqrt{305}}{-32}
=-\frac{\sqrt{305}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{305}}{2*-16}=\frac{0+8\sqrt{305}}{-32}
=\frac{8\sqrt{305}}{-32}
=\frac{\sqrt{305}}{-4}
$